Contents

Whole Numbers  BODMAS  Ordering Mathematical Operations
The BODMAS acronym is for:
B → Brackets first (parentheses)
O → Of (orders i.e. Powers and Square Roots, Cube Roots, etc.)
DM → Division and Multiplication (start from left to right)
AS → Addition and Subtraction (start from left to right) 
Exercise 2.2 (Whole Numbers) Question 1 NCERT/CBSE Solutions for Class 6th Maths
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.2) Whole Numbers Questions 1: Find the sum by suitable rearrangement:
(A) 837 + 208 + 363
(B) 1962 + 453 + 1538 + 647 
Exercise 2.2 (Whole Numbers) Question 2 NCERT/CBSE Solutions for Class 6th Maths
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.2) Whole Numbers Questions 2: Find the product by suitable rearrangement:
(A) 2 × 1768 × 50
(B) 4 × 166 × 25
(C) 8 × 291 × 125
(D) 625 × 279 × 16
(E) 285 × 5 × 60
(F) 125 × 40 × 8 × 25 
Exercise 2.2 (Whole Numbers) Question 3 NCERT/CBSE Solutions for Class 6th Maths
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.2) Whole Numbers Questions 2: Find the value of the following:
(A) 297 × 17 + 297 × 3
(B) 54279 × 92 + 8 × 54279
(C) 81265 × 169 − 81265 × 69
(D) 3845 × 5 × 782 + 769 × 25 × 218 
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Exercise 2.2 Chapter 2 Whole Numbers Question 5 NCERT Solutions for Class 6th Maths
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.2) Whole Numbers Questions 5: A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol? 
Exercise 2.2 Question 6 NCERT/CBSE Solutions for Class 6th Maths (Whole Numbers)

Exercise 2.2 (Whole Numbers) Question 7 NCERT/CBSE Solutions for Class 6th Maths
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.2) Whole Numbers Question 7:
Match the following:
(i) 425 × 136 = 425 × (6 + 30 + 100)
(A) Commutativity under multiplication
(ii) 2 × 49 × 50 = 2 × 50 × 49
(B) Commutativity under addition
(iii) 80 + 2005 + 20 = 80 + 20 + 2005
(C) Distributivity of multiplication over addition 
Exercise 2.3 Question 1 NCERT/CBSE Solutions for Class 6th Maths Chapter 2 (Whole Numbers)
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.3) Whole Numbers Question 1. 
Exercise 2.3 Question 2 NCERT/CBSE Solutions for Class 6th Maths Chapter 2 (Whole Numbers)
NCERT Solutions for Class 6th Maths (Chapter 2  Exercise 2.3) Whole Numbers Question 2. 
Exercise 2.3 Question 4 Chapter 2 (Whole Numbers) NCERT/CBSE Solutions for Class 6th Maths
NCERT Solutions for Class 6th Maths (Chapter 2) Whole Numbers Question 4 Find using distributive property:
(A) 728 × 101
(B) 5437 × 1001
(C) 824 × 25
(D) 4275 × 125
(E) 504 × 35 
Exercise 2.3 Question 5 NCERT/CBSE Solutions for Class 6th Maths Chapter 2 (Whole Numbers)
NCERT Solutions for Class 6th Maths (Chapter 2) Whole Numbers Question 5: Study the pattern and write new two steps.
1 × 8 + 1 = 9
12 × 8 + 2 = 98
123 × 8 + 3 = 987
1234 × 8 + 4 = 9876
12345 × 8 + 5 = 98765
Write the next two steps. Can you say how the pattern works?